1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 | // Could be potentially more than 3 keys in the object above const items = [{ color: 'red', type: 'tv', age: 18 }, { color: 'silver', type: 'phone', age: 20 }, { color: 'yellow', type: 'truck', age: 10 }, { color: 'blue', type: 'shirt', age: 5 }, ]; const excludes = [{ k: 'color', v: 'silver' }, { k: 'type', v: 'tv' }, { k: 'color', v: 'red' } ]; // SOLUTION const excludesMap = excludes.reduce((acc, curr) => { if (!acc[curr.k]) { acc[curr.k] = {}; } acc[curr.k][curr.v] = true; return acc; }, {}); /* color: red: true, green: true ... type: tv: true truck: true, ... */ const exclude = (items, excludes) => items.filter(item => { for (let key in item) { if (item.hasOwnProperty(key) && excludesMap[key] && excludesMap[key][item[key]]) return false; } return true; }); console.log(exclude(items, excludes)); // Output: // [{color: "yellow", type: "truck", age: 10}, // {color: "blue", type: "shirt", age: 5}] |
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