Filter objects (ES6)

// There could potentially be more than 3 keys in the object below.
const items = [{
    color: 'red',
    type: 'tv',
    age: 18
  },
  {
    color: 'silver',
    type: 'phone',
    age: 20
  },
  {
    color: 'yellow',
    type: 'truck',
    age: 10
  },
  {
    color: 'blue',
    type: 'shirt',
    age: 5
  },
];

const excludes = [{
    k: 'color',
    v: 'silver'
  },
  {
    k: 'type',
    v: 'tv'
  },
  {
    k: 'color',
    v: 'red'
  }
];

// SOLUTION

const excludesMap = excludes.reduce((acc, curr) => {
  (acc[curr.k] || (acc[curr.k] = {}))[curr.v] = true;
  return acc;
}, {});

/*
color: red: true,
       green: true ... 
type: tv: true
       truck: true, ...

*/

const exclude = (items, excludes) => items.filter(item => {
  for (const [key, value] of Object.entries(item)) {
   if(excludesMap[key]?.[value])
      return false;
  }
  return true;
});

console.log(exclude(items, excludes));
/*
  [{
    age: 10,
    color: "yellow",
    type: "truck"
  }, {
    age: 5,
    color: "blue",
    type: "shirt"
  }]
*/

Demo